'''
   20210930
   
   Robin Dawes
   
   Using *args   and using default values for parameters
'''

# the parameter name *args could be *<anything>, such as *values, *words, *pizza, or whatever you like

def fun_1(*args):
   '''prints out its arguments
   
      parameter:
         *args - any number of arguments of any types
   '''
   print("\nThese are the arguments given")
   for a in args:
      print('\t',a)
     
     
fun_1("This","works")  

fun_1("So","does","this")

fun_1() 


def fun_2(x, *args):
   '''demonstrates that we can combine named parameters and *args
   
      this requires at least one argument value
   '''
   print("\nx =", x)
   print("There are",len(args),"other arguments")
   # show that args is a tuple
   if type(args) is tuple:
      print("args is a tuple")
   else:
      print("args is not a tuple")
   print(args)
    
fun_2(3,4,5,6)      
# this would fail:
# fun_2()
      
      
def fun_3(x, y, name="anonymous"):
   '''demonstrates the use of a default value for a parameter
   
      This makes 'name' an optional parameter.  If we call this function
      without explicitly passing a value for 'name', the default value is used
   
   '''
   print("\nname:", name)
   print("x:", x,"\ty:", y)
   
# calling the function with a value for the optional parameter   
fun_3(17, 82, name = "Brady")

# calling the function without giving a value to the optional parameter
fun_3(16, 32)